# Or do anything shown above using `uncompressed` instead of `response`. With gzip.GzipFile(fileobj=response) as uncompressed:įile_header = uncompressed.read(64) # a `bytes` object # Read the first 64 bytes of the file inside the. gz (and maybe other formats) compressed data on the fly, but such an operation probably requires the HTTP server to support random access to the file. But this works well only for small files. If this seems too complicated, you may want to go simpler and store the whole download in a bytes object and then write it to a file. With (url) as response, open(file_name, 'wb') as out_file: So the most correct way to do this would be to use the function to return a file-like object that represents an HTTP response and copy it to a real file using pyfileobj. '/tmp/tmpb48zma.txt') in the `file_name` variable:įile_name, headers = (url)īut keep in mind that urlretrieve is considered legacy and might become deprecated (not sure why, though). If you need to use a proxy to download your files, you can use the ProxyHandler of the urllib module. # Download the file from `url`, save it in a temporary directory and get the In this code, we used the urlretrieve method and passed the URL of a file along with the path where we will save the file.

# Download the file from `url` and save it locally under `file_name`: The easiest way to download and save a file is to use the function: import urllib.request Let’s consider a basic example of downloading the robots.txt file from Note: urllib’s urlretrieve is considered. This includes parsing, requesting, and you guessed it downloading files. Text = code('utf-8') # a `str` this step can't be used if data is binary Python’s urllib library offers a range of functions designed to handle common URL-related tasks. If you want to obtain the contents of a web page into a variable, just read the response of : import urllib.requestĭata = response.read() # a `bytes` object

Python download file from url and save